Self Ionization of water
Hello fam! We are here again for another lesson. I believe that we have been learning a lot from the discussions that we have been having on this page. If you have been benefitting from our lessons here, kindly like the page and share to help us reach a wider audience. It has been my privilege to lead us on this voyage of learning chemistry with simplicity and ease.
Yesterday, we were able to see that the products of an acid base reaction were in themselves conjugate acids or bases. We can then write a general reaction in the form;
HA(aq) + :BH (aq)-->BH2^+(aq) + A^-(aq)
Acid Base
BH2^+ may become :BH by loss of a proton hence it is the conjugate acid of :BH.
A^- could become HA by accepting a proton hence it is the conjugate base of HA.
Is this fact clear? I believe that repetition is the key to assimilation. That’s why I have reiterated this fact many times over and I have taken my time to emphasize and reemphasize on key concepts that I want you to internalize.
I told you a few days ago that water could act both as an acid and as a base. Now I want to introduce you to a concept that is called the self ionization of water. This concept would prove to be very useful soon hence you need it in your tool kit.
Let us look at the following reaction;
H2O(l) + H2O (l)-->H3O^+(aq) + OH^-(aq)
Clearly, this reaction involves two water molecules. One water molecule is acting as an acid (by donating a proton) while the other water molecule is acting as a base (by accepting a proton). We can write the equilibrium expression for this reaction as follows;
Kw = [H3O^+] [OH^-]/[H2O]^2
Remember that liquids do not appear in the equilibrium expression (Refer to the introductory lesson on equilibrium on 19/06/2023 on the page timeline).
Thus we have that;
Kw = [H3O^+] [OH^-]
The process just described is called the self ionization of water or AUTOPROTOLYSIS and this self ionization only occur to a small extent in water. This reaction above justifies the fact that water is AMPHIPROTIC, that is, water could act as an acid or base depending on the unique circumstances of the reaction(This was demonstrated in the lesson on 3/7/2023 on the page timeline).
Experimentally at 25 degrees Celsius(room temperature), it has been determined that in pure water;
[H3O^+] = 1 *10^-7 M
[OH^-] = 1 * 10^-7 M
Then it follows that;
Kw = (1 *10^-7) (1 *10^-7)
Kw = 1 * 10^-14
The value 1 * 10^-14 is otherwise known as the ion product of water.
One important thing that we should take away from this lesson is that the concentrations of oxonium ion and hydroxide ions are equal in water. This is our definition of neutrality.
Salient point:
Water is neutral because;
[H3O^+] = [OH^-] = 1 * 10^-7 M
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